## Monday, June 15, 2009

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- Ariel Goldberg
- My name is Ariel Goldberg and I have been a GMAT tutor for eight years. I have taken the GMAT more than twenty times and scored into the 99th percentile; I like to share my GMAT knowledge with everybody. One of the things I like is to write GMAT quant questions that do reflect the changes in the test. The questions sold by some prep services are outdated in that they reflect the GMAT of three or four years ago, before Pearson took over. So that is where I come in, I provide people with good, real-looking GMAT questions.

Two things will solve this guy faster: 1) know that a regular hexagon can be divided into six equal equilateral triangles, 2) know the formula used to calculate the area of an equilateral triangle using the side as a variable.

ReplyDeleteAnswer is D

ReplyDeleteI am getting 32Pi..

ReplyDeletearea of equilateral triangle = 4root3

=0.5 X x/2 X (root3)/2 X x

x=4root2

area of circle = pi x X x

= 32pi

what gives?

area of an equil triangle is [(side^2)*(sq root 3)]/4. so 6*[(side^2)*(sq root 3)]/4 = 24*(sq root 3). Solve for side = 4, which also = radius of circle. pi r^2 = 16 pi.

ReplyDeleteOA D

ReplyDeleteArea of 6 EQ triangle = 24 sqrt 3

ReplyDeleteArea of 1 Eq Triangle = 4 sqrt 3

0.5 * (2 x)* sqrt (3) x = 4 sqrt 3

x = 2

Area of circle pi (2 x)^2 = 16 pi

Assumed The length of equ triangle = 2x which equals the radii of the circle