tag:blogger.com,1999:blog-8818940027069843379.post6614488509746465047..comments2023-09-20T00:55:46.172-07:00Comments on GMAT QUANT PROBLEMS - GMAT TUTORING arigoldberg80@gmail.com: Problem 50 - GMAT GeometryAriel Goldberghttp://www.blogger.com/profile/05729756898269014290noreply@blogger.comBlogger6125tag:blogger.com,1999:blog-8818940027069843379.post-80104143843853666032009-11-13T00:03:32.867-08:002009-11-13T00:03:32.867-08:00Area of 6 EQ triangle = 24 sqrt 3
Area of 1 Eq Tri...Area of 6 EQ triangle = 24 sqrt 3<br />Area of 1 Eq Triangle = 4 sqrt 3<br />0.5 * (2 x)* sqrt (3) x = 4 sqrt 3 <br />x = 2 <br />Area of circle pi (2 x)^2 = 16 pi<br />Assumed The length of equ triangle = 2x which equals the radii of the circleRommelhttps://www.blogger.com/profile/12810007412630821248noreply@blogger.comtag:blogger.com,1999:blog-8818940027069843379.post-6811340803706660292009-10-05T02:15:07.368-07:002009-10-05T02:15:07.368-07:00OA DOA DBhushan S.https://www.blogger.com/profile/03894137018151044440noreply@blogger.comtag:blogger.com,1999:blog-8818940027069843379.post-76418723580324090552009-09-30T13:45:11.546-07:002009-09-30T13:45:11.546-07:00area of an equil triangle is [(side^2)*(sq root 3)...area of an equil triangle is [(side^2)*(sq root 3)]/4. so 6*[(side^2)*(sq root 3)]/4 = 24*(sq root 3). Solve for side = 4, which also = radius of circle. pi r^2 = 16 pi.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-8818940027069843379.post-2474928895582664342009-09-29T19:38:55.085-07:002009-09-29T19:38:55.085-07:00I am getting 32Pi..
area of equilateral triangle =...I am getting 32Pi..<br />area of equilateral triangle = 4root3<br />=0.5 X x/2 X (root3)/2 X x<br />x=4root2<br />area of circle = pi x X x<br />= 32pi<br /><br />what gives?Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-8818940027069843379.post-15132584645366867312009-09-23T20:40:25.408-07:002009-09-23T20:40:25.408-07:00Answer is DAnswer is DAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-8818940027069843379.post-64935896029360164472009-06-15T16:44:11.170-07:002009-06-15T16:44:11.170-07:00Two things will solve this guy faster: 1) know tha...Two things will solve this guy faster: 1) know that a regular hexagon can be divided into six equal equilateral triangles, 2) know the formula used to calculate the area of an equilateral triangle using the side as a variable.Anonymousnoreply@blogger.com