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A more crude method is by POE: We can calc AB= sqrt 3, hence the perimeter =(sqrt 3+1+some term)x now bc^2 + cd^2 = 4x^2 - choices A and B are gone, Choice C: (2Sqrt2)^2 = 4x^2 suffices.
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AB = sqrt(3) * x
ReplyDelete(AB, BD) = 30 degrees
(AD, DB) = 60 degrees
BCD is an isoscless traingle.
BC = CD = x/sqrt(2)
Permiter = x( 1 + sqrt(3) + sqrt(2))
B it is.
Hey Blaoism, good reasoning but you forgot to add one sqrt(2), so answer is C.
ReplyDeleteme too :(....forgot to add one sqrt(2)
ReplyDeleteA more crude method is by POE:
ReplyDeleteWe can calc AB= sqrt 3, hence the
perimeter =(sqrt 3+1+some term)x
now bc^2 + cd^2 = 4x^2 - choices A and B are gone, Choice C: (2Sqrt2)^2 = 4x^2 suffices.
Not the best method but works!
answer =c
ReplyDeleteVery informative ..Good post..
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