Points R, S, T, U, V, W, and X lie from left to right on a number line. The distances between any two consecutive points are equal. If R = -(2^12), and
S = -(2^10), which of the points equals 2^13?
(A) T
(B) U
(C) V
(D) W
(E) X
Subscribe to:
Post Comments (Atom)
d = 3.2^10
ReplyDeleteT = 2^11
U = 5.2^10
W = 8.2^10 = 2^13
Dear Blaoism, can you tell me plz how do you get the distance s * 2^10? I understand that this is a difference, but without calculator I dont know how to arrive at this number.
ReplyDeletethe answer is v, the series given is R, S, T, U, V, W, X. The 5th element is V and the answer is V. V= 2^13
ReplyDeleteis V because
ReplyDeleter is around -4k
s is around -1k
hence the difference between each number is circa 3k
t should be c2k, u c5k and V c8k ..
V
-2^12 + n(3.2^10)= 2^13
ReplyDeletesolve for n=4
a,a+d,a+2d,a+3d,a+4d
5th term=V
-2^12 + (n-1)(3.2^10)= 2^13 ie. an=a1+(n-1)d
ReplyDelete-2^2 + (n-1)(3)= 2^3
(n-1)(3)= 12
n=5
so fifth term i.e V