## Tuesday, October 6, 2009

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- Ariel Goldberg
- My name is Ariel Goldberg and I have been a GMAT tutor for eight years. I have taken the GMAT more than twenty times and scored into the 99th percentile; I like to share my GMAT knowledge with everybody. One of the things I like is to write GMAT quant questions that do reflect the changes in the test. The questions sold by some prep services are outdated in that they reflect the GMAT of three or four years ago, before Pearson took over. So that is where I come in, I provide people with good, real-looking GMAT questions.

AB = sqrt(3) * x

ReplyDelete(AB, BD) = 30 degrees

(AD, DB) = 60 degrees

BCD is an isoscless traingle.

BC = CD = x/sqrt(2)

Permiter = x( 1 + sqrt(3) + sqrt(2))

B it is.

Hey Blaoism, good reasoning but you forgot to add one sqrt(2), so answer is C.

ReplyDeleteme too :(....forgot to add one sqrt(2)

ReplyDeleteA more crude method is by POE:

ReplyDeleteWe can calc AB= sqrt 3, hence the

perimeter =(sqrt 3+1+some term)x

now bc^2 + cd^2 = 4x^2 - choices A and B are gone, Choice C: (2Sqrt2)^2 = 4x^2 suffices.

Not the best method but works!

answer =c

ReplyDeleteVery informative ..Good post..

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