Jamal and Mary read a total of 100 books and no book was read by both of them. If Jamal found 40% of the books he read boring and Mary found 50% of the books she read boring, and together they found 44% of the 100 books boring, what percent of the 100 books was read by Mary?
(A) 66 2/3 %
(B) 60 %
(C) 58 %
(D) 48 %
(E) 40 %
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Set up a table (mary, jamal on the left; boring n not-boring on the right)
ReplyDelete40 pc is the answer
0.4x+0.5(100-x)=44
ReplyDeletex=60
Mary:100-x=40